how to check if an array contains the elements from a sub array

Question

i want to check i an array contains the elements of any sub array, i.e. array1 = [10,11,12] array 2 = [[10, 11],[20, 21],[30, 31],[40, 41]];

array1 will be checked in series by each of array2's sub arrays and if the sub array elements are also in the array1 then to return true.

i've tried thing like:

      array2.some((arr) => {
        return arr.every((square) => {
          return array1.includes(square);
        });
      });

or

    for (let elem of array2) {
        if (elem.every((x) => array1.includes(x))) {
          return false;
        } else {
          return true;
        }
      }

any advice would be helpfull. thank you

What is the problem you are facing? Your snippet one looks okay. In the snippet two, in case of subarray match you are returning false which looks odd. — Hassan Imam
– Hassan Imam, Commented Feb 11, 2022 at 19:35
do you want to return true if you have [11, 12] in array2? — Nina Scholz
– Nina Scholz, Commented Feb 11, 2022 at 19:36
Are you trying to see if any of the items in array1 exist in a sub-array of array2 or are you trying to see if all of them match a sub-array of array2? — Abir Taheer
– Abir Taheer, Commented Feb 11, 2022 at 20:03

Nina Scholz · Accepted Answer · 2022-02-11 19:46:16Z

2

You need to iterate the sub array as well for the sequence.

const
    array1 = [10, 11, 12],
    array2 = [[10, 11], [20, 21], [30, 31], [40, 41]],
    result = array2.some(a => {
        for (let i = 0, l = array1.length - 1; i < l; i++) {
            if (a.every((v, j) => v === array1[i + j])) return true;
        }
        return false;        
    });

console.log(result);

answered Feb 11, 2022 at 19:46

Nina Scholz

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