Replace value in a configuration file via bash

Question

I have to replace the numeric values contained into a rhel configuration file through a bash script:

auth        required      pam_tally2.so onerr=fail deny=5 even_deny_root unlock_time=600 root_unlock_time=600

As long as these values are not the same, I'm unable to match a pattern. How can I find and replace (for example) unlock_time=600 with unlock_time=1000?

sseLtaH · Accepted Answer · 2022-03-02 08:42:15Z

1

Using sed

$ sed 's/\(\<unlock_time=\)[^ ]*/\11000/' input_file
auth        required      pam_tally2.so onerr=fail deny=5 even_deny_root unlock_time=1000 root_unlock_time=600

answered Mar 2, 2022 at 8:42

sseLtaH

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Antonio Petricca · Accepted Answer · 2022-03-02 08:41:24Z

1

Here is the solution:

sed -rni 's/^(.*\bunlock_time\b=)([0-9]+)(.*)$/\1<PARAM_VALUE>\3/p' <CONFIG_FILE>

answered Mar 2, 2022 at 8:41

Antonio Petricca

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1 Comment

Tex'N'Duet Over a year ago

Thank you! This is a good solution. The only thing is that replace everything in the file and leave only the line that matches the pattern

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