Convert Array to Object for table Schema

Question

What is the best way to convert:

["Foo", "Bar", "John"]

To:

{
Foo: { name: 'Foo', index: 0, type: 'String' },
Bar: { name: 'Bar', index: 1, type: 'String' },
John: { name: 'John', index: 2, type: 'String' },
}

I believe I need to utilize

array.map()

but am not sure how to structure my mapping function. Any insight would be helpful.

Ele · Accepted Answer · 2022-03-23 21:26:13Z

1

You can the function Array.prototype.reduce as follow.

const source = ["Foo", "Bar", "John"],
  capitalize = string => string.charAt(0).toUpperCase() + string.slice(1),
  result = source.reduce((a, name, index) => ({...a, [name]: {name, index, type: capitalize(typeof name)}}), {});
  
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

edited Mar 23, 2022 at 21:26

answered Mar 23, 2022 at 20:21

Ele

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6 Comments

NicoloCode Over a year ago

Thank you! super helpful. The result needs to be an object, although that wasn't clear in the question. I have updated the exact structure needed.

cmgchess Over a year ago

@NicoloCode you can use reduce for that. something like given that keynames are distinct stackoverflow.com/questions/64188099/…

Ele Over a year ago

@NicoloCode you cannot have multiple repeated keys within an object.

Ele Over a year ago

@NicoloCode the names will be different from each other?

NicoloCode Over a year ago

Yes, apologies as I cannot provide my original array as it's confidential. I have updated it to contain strings other than foo

|

Sergey Mell · Accepted Answer · 2022-03-23 21:43:39Z

0

I think you could do as follows

const array = ["Foo", "Bar", "John"];
Object.fromEntries(
   array
   .map((el, index) => {
     return [el, {name: el, index, type: el.constructor.name}]
   })
)

Here you can find an example snippet:

const array = ["Foo", "Bar", "John"];
const result = Object.fromEntries(
   array
   .map((el, index) => {
     return [el, {name: el, index, type: el.constructor.name}]
   })
);
console.log(result);

edited Mar 23, 2022 at 21:43

answered Mar 23, 2022 at 21:24

Sergey Mell

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3 Comments

Sergey Mell Over a year ago

@NicoloCode, do you need any additional explanations?

NicoloCode Over a year ago

Thanks for the answer. I think I may need the names without the "", including Foo, name, index, and type. Is there a simple fix for this?

Sergey Mell Over a year ago

It's just an object representation. It will work exactly the same as your example. If you copy the code and run it in browser console, you'll see the object properties without "" and singlequouted strings

Serge · Accepted Answer · 2022-03-23 23:00:45Z

0

your json is not valid , so if you need the valid json like this

[{"name":"Foo","index":0,"type":"string"},{"name":"Foo","index":1,"type":"string"},{"name":"Foo","index":2,"type":"string"}]

you can use this code

var result=[];
arr.forEach( (element,i )=> {
  result.push( {name:element, index:i, type: typeof element});
 });

UPDATE

for your another json

var jarr=["Foo", "Bar", "John"]

you can use this code

var result = {};
jarr.forEach((element, i) => {
  result[element] = { name: element, index: i, type: typeof element };
});

result

{
  "Foo": {
    "name": "Foo",
    "index": 0,
    "type": "string"
  },
  "Bar": {
    "name": "Bar",
    "index": 1,
    "type": "string"
  },
  "John": {
    "name": "John",
    "index": 2,
    "type": "string"
  }
}

edited Mar 23, 2022 at 23:00

answered Mar 23, 2022 at 21:20

Serge

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