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I am working with the following array of objects and I am trying to run a function with forEach. However, I don't want to destroy the original tbl1. Hence, I made a copy of tbl1 in tbl2 and I am running forEach on tbl2.

What surprises me, if I run a forEach on tbl2 so that I can preserve the tbl1 structure, it also takes place in tbl1 which I don't want.

const tbl1 = [{ "Month": 1, "Value": 100 }, { "Month": 2, "Value": 200 }, { "Month": 3, "Value": 300 }]

const tbl2 = tbl1;

tbl2.forEach(
    (d)=>{d.newCol=d.Month*152;});

console.log(tbl1,tbl2);

Is it possible to run forEach on a copy table without destroying the source table?

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  • You're likely surprised to learn that tbl2 = tbl1 does not make a copy. Rather, now tbl2 is a variable that refers to the same array that tbl1 does. Commented Apr 28, 2022 at 18:19

2 Answers 2

3

you can use map

const tbl1 = [{ "Month": 1, "Value": 100 }, { "Month": 2, "Value": 200 }, { "Month": 3, "Value": 300 }]

const tbl2 = tbl1.map(d => {
  return {
   ...d,
   newCol: d.Month*152
  }
})


console.log(tbl1,tbl2);
If you want to do a deep copy you should use JSON.parse and JSON.stringify

const tbl1 = [{ "Month": 1, "Value": 100 }, { "Month": 2, "Value": 200 }, { "Month": 3, "Value": 300 }]

const tbl2 = JSON.parse(JSON.stringify(tbl1));

tbl2.forEach(
    (d)=>{d.newCol=d.Month*152;});

console.log(tbl1,tbl2);

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1 Comment

Many thanks for showing JSON.parse(JSON.stringify()).
2

That is because when you write const tbl2 = tbl1;, it doesn't clone the array, rather takes a reference to the original. So when you modify the the reference, the original gets modified as well.

2 Comments

Wow I did not know that. Thanks. What is a convenient way take tbl1 in a var/const where it does not refer to the original structure anymore and if I run forEach it does not hurt the source table.
@smpa01 use map to deep copy/clone.

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