jq transform to array and sort

Question

Suppose I have the following input.log file:

{"foo": "1", "foo2": "2"}
{"foo": "3", "foo2": "4"}
{"foo": "5", "foo2": "6"}
{"foo": "7", "foo2": "8"}

I want to parse this using jq and sort the result based on the value of some common key, lets say the "foo" key.

How could I accomplish that?

Use --slurp and sort_by: jq -sc 'sort_by(.foo)[]' input.log Demo — pmf
– pmf, Commented May 27, 2022 at 23:02

ikegami · Accepted Answer · 2022-05-28 01:48:41Z

1

To sort, you need an array, which you can obtain using --slurp/-s.

jq -sc 'sort_by( .foo )[]' input.log

Demo on jqplay

answered May 28, 2022 at 1:48

ikegami

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