How to invoke Lambda function using boto3 and passing parameters

Question

This time I'm looking for passing parameters to lambda invoke using boto3.client instead of make a request to API gateway.

Assume I developed a lambda function that can be invoked through api get. ie: https://linktolambda/<parameter> and now I am trying to access same lambda function from another one using boto3 client.

I have read documentation from:

I have read stackoverflow questions, reddit questions, medium posts, etc. but I haven't found what I'm looking for.

Thanks in advance.

Perhaps you could explain why the linked documentation did not help. The first link, for example, does exactly what you appear to be asking for (one Lambda function can synchronously or asynchronously invoke a second Lambda function without having to do it via API Gateway). — jarmod
– jarmod, Commented Jun 15, 2022 at 0:37

hoangdv · Accepted Answer · 2022-06-15 03:57:44Z

4

If you don't want to update your lambda function, just simulate APIGateway event object by boto3 client:

If your api looks like https://linktolambda/{id} (ex: https://linktolambda/123456)

You will invoke with this code:

        payload = { "pathParameters": { "id":"123456" } } 
        result = client.invoke(FunctionName=conf.lambda_function_name,
                    InvocationType='RequestResponse',                                      
                    Payload=json.dumps(payload))

Or your API look like https://linktolambda?id=123456

        payload = { "queryStringParameters": { "id":"123456" } } 
        result = client.invoke(FunctionName=conf.lambda_function_name,
                    InvocationType='RequestResponse',                                      
                    Payload=json.dumps(payload))

answered Jun 15, 2022 at 3:57

hoangdv

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4 Comments

ninsignares Over a year ago

Thank you for your response. As we try your method, we get a 200 type response from invoke but a type 500 error in payload. Our lambda api looks like https://linktolambda/subpath/{id}. I have tried with all type of combinations of parameters explained in: link, always returning a 500 response.

ninsignares Over a year ago

This is the final response we get:

{'headers': {},'multiValueHeaders': {}, 'statusCode': 500, 'body': '{"Code":"InternalServerError","Message":"Unknown request."}'}

hoangdv Over a year ago

@ninsignares are you using chalice to build the lambda function? github.com/aws/chalice/issues/1337

ninsignares Over a year ago

Yes I am. I use chalice to build and deploy my lambda function. I have tried github solution without success. I guess is more efficient and good practice to invoke lambdas instead to request apis.

Irene · Accepted Answer · 2022-06-15 14:08:14Z

0

There are actually two methods in BOTO3 that can be used to invoke a Lambda function. The first is: [invoke(**kwargs)][1]

and the second is: [invoke_async(**kwargs)][2]

See:

https://boto3.amazonaws.com/v1/documentation/api/latest/reference/services/lambda.html#Lambda.Client.invoke

https://boto3.amazonaws.com/v1/documentation/api/latest/reference/services/lambda.html#Lambda.Client.invoke_async

The first method makes a synchronous call and the second method makes an asynchronous call. Once your Lambda function has been deployed, you can use either method to invoke it.

answered Jun 15, 2022 at 14:08

Irene

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1 Comment

mherzog Over a year ago

When I went to the invoke_async link given in this answer, the page states that invoke_async is deprecated. Instead, you can use the invoke method with the parameter InvocationType='Event'

paimoe · Accepted Answer · 2024-02-07 23:43:09Z

0

Look at the Official AWS Code Example Github. For Python Code examples look here:

https://github.com/awsdocs/aws-doc-sdk-examples/tree/main/python

You can find how to invoke a Lambda function and pass parameters (exactly what you are looking for) in this code example:

https://github.com/awsdocs/aws-doc-sdk-examples/blob/main/python/example_code/lambda/lambda_basics.py

Look for the method invoke_function.

edited Feb 7, 2024 at 23:43

paimoe

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answered Jun 14, 2022 at 23:54

smac2020

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