javascript expression to check if array includes only a specified type

Question

Hello everyone I struggling to create an expression to check if a specific array includes only a specified type values.Here is what I tried :

const isArrayOfType = (arr, type) =>
  arr.forEach((item) => typeof item == type) ? true : false;

const arr = [1, 2, 3];
const typ = 'number';

console.log(isArrayOfType(arr, typ));

The main goal is to not use return in the expression.

Jamiec · Accepted Answer · 2022-07-18 10:07:42Z

2

forEach doesnt return anything, I think you're looking for every (and the ternary operator is unecessary as it already returns a boolean)

const isArrayOfType = (arr, type) =>
  arr.every((item) => typeof item == type);

const arr = [1, 2, 3];
const typ = 'number';

console.log(isArrayOfType(arr, typ));
console.log(isArrayOfType(["one",2,3], typ));

answered Jul 18, 2022 at 10:07

Jamiec

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