Matplotlib having different x ticks that the index from numpy array

Question

I want to plot a numpy array but I want to change the x ticks value of the plot. I want to have negative index, from instance for an array of size 20, I want to have x ticks in range of [-9,10]

I tried this code:

import numpy as np
import matplotlib.pyplot as plt

size = 20

seq = np.full(size, 1)
for i in range(size//2, size):
    seq[i] = 0

fig, ax = plt.subplots()
ax.plot(seq)
ax.set_xlabel('x')
ax.set_xticks(np.arange(-size//2+1, size//2+1, 1))
plt.show()

But I have an unexpected result:

Said Taghadouini · Accepted Answer · 2022-07-28 16:02:14Z

1

You can use plt.xticks() instead of ax.set_xticks()

import numpy as np
import matplotlib.pyplot as plt

size = 20

seq = np.full(size, 1)
for i in range(size//2, size):
    seq[i] = 0

fig, ax = plt.subplots()
ax.plot(seq)
ax.set_xlabel('x')
plt.xticks(labels=np.arange(-size//2+1, size//2+1, 1),
           ticks=range(size),
           rotation=0)
plt.show()

result

edited Jul 28, 2022 at 16:02

answered Jul 28, 2022 at 15:59

Said Taghadouini

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1 Comment

Yannis Sauzeau Over a year ago

I prefer used ax.set_xticks() but with your solution I see that I can use ax.set_xticklabels, so with ax.set_xticks(range(size)) and ax.set_xticklabels(np.arange(-size//2+1, size//2+1, 1)), it's work as excepted, thank you for your help !

Yannis Sauzeau · Accepted Answer · 2022-07-28 12:59:59Z

0

I resolved the problem using ax.plot(np.arange(-size//2+1, size//2+1, 1), seq) that plot the numpy array with the x ticks I wanted, the result:

answered Jul 28, 2022 at 12:59

Yannis Sauzeau

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