namespace t {
class A {};
}
How can create an object of class A?
EDIT :
namespace beta {
class TESSDLL_API TessBaseAPI
{
public:
TessBaseAPI();
virtual ~TessBaseAPI();
}
}
This is the class defined inside beta namespace . Now how do i call the constructor? is
tess = new beta::TessBaseAPI();
correct?
As you would normally do. The only difference is that A is inside the namespace t. So you can :
use the scope resolution operator every time you want to use A :
t::A a;
use the using directive
using namespace t;
A a;
or, as Luc Danton pointed out use the using declaration
using t::A;
A a;
following your edit :
Assuming that your class declaration is ending with a ; as in
namespace beta {
class TESSDLL_API TessBaseAPI
{
public:
TessBaseAPI();
virtual ~TessBaseAPI();
};
}
Then the correct way to call the constructor is :
beta::TessBaseAPI * tess = beta::TessBaseAPI();
or
beta::TessBaseAPI tess;
using t::A; is called a using declaration while using namespace t; is a using directive.Either
namespace t
{
A a;
}
or
t::A a;
In the first case a lives inside namespace t (in fact its full name is ::t::a).
In the second case a is global.
(note: your class A{} is missing a ; after })
namespace t
{
class A {} a;
A another_a;
}
Now use t::a or t::another_a.
If you want to make another object:
t::A another_a_out_of_namespace_scope;
Use a semicolon after the declaration of the class, and use:
t::A my_object;
muntoo's answer allows you to create a single instance of the class and is also correct.
For an object named x;
t::A x;
