I am trying to apply textblob like so:
df['newtext'] = df['text'].apply(lambda x: TextBlob(x))
but that tokenizes "text" and returns (I, ', v, e, , b, e, e, n, , u, s, i, n, g,...) instead of a textblob object. Any idea why this is so?
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We can join it again like this... "".join(TextBlob(x)) ... nah?Sachin Kohli– Sachin Kohli2022-09-25 17:32:24 +00:00Commented Sep 25, 2022 at 17:32
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1 Answer
Ultimately when you are using the apply method, you are returning a TextBlob object instead of a String and Pandas doesn't know exactly what to do with it (which is why you get the weird behavior)
To solve your issue, simply surround the object being returned by TextBlob with str(), and it will work. Check the below example
import pandas as pd
from textblob import TextBlob
d = {'text': ["I'm learning", "I love coding"], 'num': [2, 4]}
df = pd.DataFrame(data=d)
print(df)
df['newText'] = df['text'].apply(lambda x:str(TextBlob(x)))
print(df)
Output will look like this:
If you don't use the str() like:
df['newText'] = df['text'].apply(lambda x:(TextBlob(x)))
The ouput will look like:
