Input:
var arr = [{ fName: "a" }, { fName: 1 }, { fName: "A" }];
Expected Output
var arr = [{ fName: 1 }, { fName: "A" },{ fName: "a" }];
supposed key fName is a employee name and we want to sort this object [1,'A','a'] like this but in object form.
how to do this?
You can give precedence to numbers over strings checking the typeof variable, and returning -1 or 1 accordingly:
| compareFn(a, b) return value | sort order |
|---|---|
| > 0 | sort a after b |
| < 0 | sort a before b |
| === 0 | keep original order of a and b |
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
const arr = [{ fName: "a" }, { fName: 3 }, { fName: "A" }, { fName: 1 }];
console.log(
arr.sort((a, b) => {
if (typeof a.fName === 'number' && typeof b.fName !== 'number') {
return -1
}
if (typeof a.fName !== 'number' && typeof b.fName === 'number') {
return 1
}
if (a.fName < b.fName) {
return -1
}
if (a.fName > b.fName) {
return 1
}
if (b.fName === a.fName) {
return 0
}
})
)You just need to come up with a proper sorting function.
const sortByFName = (a, b) => a.fName
.toString()
.localeCompare(
b.fName.toString(), 'en', {
caseFirst: 'upper'
}
)
const result = [{
fName: "a"
}, {
fName: 1
}, {
fName: "A"
}].sort(sortByFName)
console.log(JSON.stringify(result))You can use Array.prototype.sort to sort an array using any comparison code you want.
For example:
objArray.sort((a, b) => {
// Some code for comparison
});
Learn more about the sort function: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/sort
Array.prototype.sort()