bash script loop through two variables in lock step

Question

I'm trying to write a bash script that loops through two variables:

#!/bin/bash
for i in sd fd dir && j in storage file director
 do
   echo "restarting bacula $j daemon"
   /sbin/service bacula-$i restart
   echo
done

The code above is obviously wrong. But I want i & j to move in lock step with one another. Can someone help me with a way to achieve this?

Thanks

John1024 · Accepted Answer · 2015-05-14 01:25:13Z

4

#!/bin/bash
a=(sd fd dir)
b=(storage file director)
for k in "${!a[@]}"
do
   echo "restarting bacula ${b[k]} daemon"
   /sbin/service "bacula-${a[k]}" restart
   echo
done

answered May 14, 2015 at 1:25

John1024

115k15 gold badges152 silver badges183 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Etan Reisner · Accepted Answer · 2015-05-14 01:25:21Z

0

Use arrays and a manual loop.

a=(sd fd dir)
b=(storage file director)

for ((i = 0; i <= ${#a}; i++)); do
    echo "restarting bacula ${b[i]} daemon"
    /sbin/service "bacula-${a[i]}" restart
done

answered May 14, 2015 at 1:25

Etan Reisner

81.7k8 gold badges120 silver badges154 bronze badges

Collectives™ on Stack Overflow

bash script loop through two variables in lock step

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related