can someone help me, I need to remove alphabets from array of strings and convert it to array of numbers, this is what I did but not getting it right.
const fruits = [" 2", " 1", " 0", "remove this", " 1", " 2", " 0", " 0", " 1", " 0"];
let text = fruits.toString();
var f = text.replace(/[a-z-A-Z]/g, "");
var h = f.split(",");
h.filter(n => n)
console.log(h)you can multiply string by 1 to convert and check if it is number
const fruits = [" 2", " 1", " 0", "remove this", " 1", " 2", " 0", " 0", " 1", " 0"];
console.log(fruits.filter((v)=> !Number.isNaN(v*1)).map((v)=> Number(v)));
Number(v) * 1 -> Number(v)Convert them to Numbers and remove those that aren't:
nums = fruits.map(Number).filter(x => !Number.isNaN(x))
You can use isNaN function to check if a variable is number or not. Here is the code:
const fruits = [" 2", " 1", " 0", "remove this", " 1", " 2", " 0", " 0", " 1", " 0"];
var nums=[]; // array for numbers
for( let i = 0; i < fruits.length ;i++){
if(!isNaN(fruits[i])) // check if the value is number or not
nums.push(parseInt(fruits[i]));//add numbers in array with int parsing
}
console.log(nums) //print the array of numbers only
" "that you have as the 4th element? Would help if you showed your expected output