Convert string type to Instance type [duplicate]

Question

I have a dict(image attached below): [1]: https://i.sstatic.net/n3SYv.png

The keys of the dict is a dataframe. When trying to upload this dict to json I had to convert column a to string type from interval type. But when I want to use the json I want to convert the values of column a back to interval type. Below are the things I've tried:

k = dict.keys()
for keys in k:
   dict[keys]["a"] = dict[keys]["a"].astype("interval")

But it throws the below error: TypeError: type <class 'str'> with value (-inf, -9999999.0] is not an interval

Can you please help me with the way to convert column a values from string to Interval types?

I think this question has been answered already but without inf: stackoverflow.com/questions/65295837/… inf can be converted with np.array([np.inf]).astype(int)[0] or math.inf (or -math.inf for negative infinity) — Ori Yarden PhD
– Ori Yarden PhD, Commented Jan 3, 2023 at 16:11

sanchit sherawat · Accepted Answer · 2023-01-04 10:07:25Z

-1

(See Security of Python's eval() on untrusted strings?)

>>> class Foo(object):
...     pass
... 
>>> eval("Foo")
<class '__main__.Foo'>

edited Jan 4, 2023 at 10:07

answered Jan 4, 2023 at 10:03

sanchit sherawat

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1 Comment

Martijn Pieters Over a year ago

You are only looking at the question title, and not the question details. They are not asking for arbitrary conversions.

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