php replace non matches from two arrays

Question

How do you replace all non matches from one array that are not defined within the other array, i have kind of got working but its not exactly right. as i will show you.

the result is, but wrong.

- - £ 8 - - - - - - - -

The required result should be

 £ 8 - -

this is how my code is

$vals_to_keep = array(8, 'y', '£');

$replace_if_not_found = array('£', 8, '#', 't'); // replace if not in above array

$result = '';

foreach ($replace_if_not_found as $d) {
 foreach ($vals_to_keep as $ok) {
    if(strcmp($d, $ok) == 0){
    $result .= $d . " ";
    }else 
    $result .= str_replace($d, $ok ,'-') . " ";
    }
}
echo $result;

Mahesh · Accepted Answer · 2011-10-02 13:08:52Z

1

use in_array http://php.net/manual/en/function.in-array.php

foreach ($replace_if_not_found as $d) {
if (in_array($d, $vals_to_keep)) 
    $result .= $d . " ";
else 
    $result .= str_replace($d, $ok ,'-') . " ";
}

answered Oct 2, 2011 at 13:08

Mahesh

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Comments

salathe · Accepted Answer · 2011-10-02 13:07:57Z

0

You could loop over all of the items in $replace_if_not_found replacing them with -, or not, as appropriate.

Using closure in PHP 5.3 or above

$result = array_map(function($item) use ($vals_to_keep) {
    return in_array($item, $vals_to_keep, TRUE) ? $item : '-';
}, $replace_if_not_found);
echo implode(' ', $result);

Using a foreach loop

$result = array();
foreach ($replace_if_not_found as $item) {
    if (in_array($item, $vals_to_keep, TRUE)) {
        $result[] = $item;
    } else {
        $result[] = '-';
    }
}
echo implode(' ', $result;

edited Oct 2, 2011 at 13:07

answered Oct 2, 2011 at 13:02

salathe

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2 Comments

david Over a year ago

what happened to array_pad array_intersect form your first answer, that was a very neat solution

salathe Over a year ago

it wouldn't work for arrays like array('£', 8, 'a', 'b', '£')

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