compare array values for a if statement php

Question

im having a list of names james,steve,manson,charles in a array and im using the explode function to separate them.

 $pieces = explode(",", $full);

foreach ($pieces as $p ){

    $piece[]=$p;
}

the problem that im having is that i can access the variables as

$piece[0];
$piece[1];

but the order differs time to time based on the input therefore i cant do a comparison. can someone suggest how to set the values so i can do the comparison as below

 if ($piece==='manson'){
//do something;
}else{
//do something
}

 if ($piece==='steve'){
//do something;
}else{
//do something
}

Looks like you are looking for switch?

Jon
– Jon

2011-10-07 18:30:47 +00:00
Commented Oct 7, 2011 at 18:30 — Jon
– Jon, Commented Oct 7, 2011 at 18:30

hakre · Accepted Answer · 2012-12-13 03:17:31Z

5

$full = 'james,steve,manson,charles';
$pieces = explode(",", $full);

using a loop

foreach($pieces as $p ) {
    // $p holds the name
    if($p==='manson') {
        //do something;
    } elseif($p==='steve') {
        //do something;
    } else {
        //do something
    }
}

also you could just check for the name in the array instead of looping

if(in_array('steve',$pieces)) {
    echo 'We have Steve in the house';
}

or as Jon has suggested using a switch

foreach($pieces as $p) {
    switch ($p) {
        case 'manson':
        case 'steve':
        case 2:
            echo "Fist pump for ".$p;
            break;
        default:
            echo "no fist in the air";
    }
}

edited Dec 13, 2012 at 3:17

hakre

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answered Oct 7, 2011 at 18:33

Phill Pafford

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1 Comment

LiveEn Over a year ago

the foreach if statement repeated same content but the in_array option worked perfectly.. Thank you very much...

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