Sorting an array of objects by a certain string value [duplicate]

You could use the .toSorted() with a custom sorting (which compares two elements of the array and returns a negative number if the first element should come before the second, a positive number if the second element should come before the first, or zero if they are equal.)
In our example: The comparison function checks if the country value of the first object is 'Canada' and the country value of the second object is not 'Canada', in which case it returns -1 to indicate that the first object should come before the second. If the opposite is true, it returns 1. If both objects have the same country value, it returns 0 to indicate that their order should not change.

const stores = [ {id: 1, name: 'Store1', country: 'USA'}, {id: 2, name: 'Store2', country: 'Canada'}, {id: 3, name: 'Store3', country: 'USA'}, {id: 4, name: 'Store4', country: 'Canada'} ];
function sortByCountryFirst(array, country) {
  return array.toSorted((a, b) => {
    if (a.country === country && b.country !== country) {
      return -1;
    } else if (a.country !== country && b.country === country) {
      return 1;
    } else {
      return 0;
    }
  });
}
console.log(sortByCountryFirst(stores, 'Canada'));

Tip: Use .toSorted() to sort an array without mutating the original array! see my answer