php list split array as options

Question

Ok so tbh the title isn't very good I just don't know how to explain what i'm trying to do in 1 short sentence so I will do my best here....

I have an array

$options = array('156656', 'bar', '235456','soft', '353636','eve', '4356563', 'evil');

I want number and name to be partnered/linked so have done this by splitting with list() ...

list($number, $name) = $options; 

echo $name . ' : ' . $number . '<br />';

which shows as

 156656 : bar

but what I need is for all to be listed like so ...

156656 : bar
235456 : soft
353636 : eve
4356563 : evil

I'm guessing this is done with a foreach but what ever I try fails

As always all help is appreciated and thanks in advance.

xdazz · Accepted Answer · 2011-10-29 05:21:06Z

2

You can use array_chunk to get sub arrays like below:

$options = array('1', 'bar', '2','soft', '3','eve', '4', 'evil');
foreach (array_chunk($options, 2) as $sub) {
     list($number, $name) = $sub; 
     echo $number . ' : ' . $name . '<br />';
}

answered Oct 29, 2011 at 5:21

xdazz

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Comments

Kerrek SB · Accepted Answer · 2011-10-29 05:11:18Z

1

How about enumerating two at a time:

for ($i = 0; 2 * $i < count($arr); ++$i)
{
  print("First: " . $arr[2 * $i] . ", Second: " $arr[2 * $i + 1]);
}

answered Oct 29, 2011 at 5:11

Kerrek SB

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2 Comments

Dizzi Over a year ago

ok I see what you mean but the number in my list isn't actually necessarily in order, maybe I will edit my question

guru Over a year ago

It doesn't matter if numbers in your list are in order or not, the above loop will still work.

Tim · Accepted Answer · 2011-10-29 05:24:26Z

0

Try using associative arrays, for this application, as well:

$options = array('156656'=>'bar', '235456'=>'soft', '353636'=>'eve', '4356563'=>'evil');

Then, you can use foreach on it as so:

foreach($options as $key=>$value){
   print("$key: $value\n");
}

answered Oct 29, 2011 at 5:24

Tim

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