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Hex string is from https://github.com/bitcoin/bitcoin/blob/d30f149360d10de31bd7f7369aa61ce8be0837b5/src/kernel/chainparams.cpp#L75C5-L75C206

I have tried the following Python 3 code but it doesn't seem to get the string expected.

bytes_data = bytes.fromhex("04678afdb0fe5548271967f1a67130b7105cd6a828e03909a67962e0ea1f61deb649f6bc3f4cef38c4f35504e51ec112de5c384df7ba0b8d578a4c702b6bf11d5f")
string_data = bytes_data.decode("ascii", errors="ignore")
print(string_data)

It's printing:

gUH'gq0\(9  ybaI?L8U\8M
                           WLp+k_

Instead of:

"The Times 03/Jan/2009 Chancellor on brink of second bailout for banks"

What am I missing?

Improve this question
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  • I'm not a bitcoin expert, but that hex string looks like an SEC1 uncompressed elliptic curve point. There is no way to get that ASCII string from that 65-byte value. Commented Oct 18 at 21:10
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