How to create array type containing values of all object properties [duplicate]

How do I create an array type that must contain all object property values (in any order) based on object definition?

Having an object type definition like this:

type ExampleObject = {
   property1: "abc",
   property2: "xyz",
   property3: "123"
}

How do I define type that is satisifed only by these values (with items in any order):

const exeampleArray = ["abc", "xyz", "123"]
const exeampleArray2 = ["xyz", "abc", "123"]
... etc

My exact scenario is a little more complicated but it might be useful to know:

This is a definition of one TableColumn

export type TableColumn<
  RowEntity extends object,
  ColumnKey extends string,
  ValueType,
> = {
  getValue: (row: RowEntity) => ValueType;
  key: ColumnKey;
};

This is a definition of table structure (column keys and their types):

export type TableStructure = {
  name: string;
  description: string;
  active: boolean;
};

Now I want to define type, which will require array of all TableColumns based on TableStructure. I was able to create a definition of object containing all TableStructure keys with corresponding TableColumn

type TableColumnsObject<
  TableStructure extends object,
  RowEntity extends object,
> = {
  [ColumnKey in keyof TableStructure]: TableColumn<
    RowEntity,
    Extract<ColumnKey, string>,
    TableStructure[ColumnKey]
  >;
};

But I now want to use have the columns in a form of an array like this:

const columns = [
  TableColumn<RowEntity, "name", string>,
  TableColumn<RowEntity, "description", string>,
  TableColumn<RowEntity, "active", boolean>
]

I am sure there must be a way to do that, but don't know how.

Again - the columns may be in any order, I just need the type to check there are all TableColumn items according to TableStructure.