PHP : foreach warning

Question

I'am executing code :

<?php
$input="ABC123";
$splits = chunk_split($input,2,"");
foreach($splits as $split)
{
$split = strrev($split);
$input = $input . $split;
}
?>

And output that i want is :

BA1C32

But it gaves me Warning.

Warning: Invalid argument supplied for foreach() in /home/WOOOOOOOOHOOOOOOOO/domains/badhamburgers.com/public_html/index.php on line 4

chuck_split return a string, you can't do a foreach on a string — malletjo
– malletjo, Commented Nov 13, 2011 at 18:37

Marcus · Accepted Answer · 2011-11-13 18:41:39Z

5

chunk_split doesn't return an array but rather a part of the string.

You should use str_split instead:

$input="ABC123";
$splits = str_split($input, 2);

And don't forget to reset your $input before the loop, else it will contain the old data aswell.

answered Nov 13, 2011 at 18:36

Marcus

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1 Comment

don't forget to reset your input or change your variable name.

Homer6 · Accepted Answer · 2011-11-13 18:40:53Z

1

It looks like http://php.net/manual/en/function.chunk-split.php returns a string, not an array. You could use str_split instead:

$input = "ABC123";
$splits = str_split( $input, 2 );
$output = "";
foreach( $splits as $split ){
   $split = strrev($split);
   $output .= $split;
}

answered Nov 13, 2011 at 18:35

Homer6

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mobius · Accepted Answer · 2011-11-13 18:36:55Z

0

As the documentation for chunk_split mentions clearly, http://php.net/manual/en/function.chunk-split.php chunk split returns a string.

foreach expects an array as first argument.

answered Nov 13, 2011 at 18:36

mobius

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