How to: a command result to a variable?
for file in find "$1" do
var = $file | cut -d/ -f6-
echo $var
...
done
-
A command result to a variable? variable=command (Where command is surrounded with `)Lewis Norton– Lewis Norton2011-11-21 15:14:35 +00:00Commented Nov 21, 2011 at 15:14
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2 Answers
A few pointers:
In shell scripts whitespace really matters. Your code var = $file is an error, since no executable var exists which knows how to process the arguments = and $file. Use
var="$file"
Instead.
To capture the output of your $file | cut -d/ -f6- pipeline you will need the following syntax:
var="$(echo $file | cut -d/ -f6-)"
In bash of recent version you can use a "here string" instead and avoid the expense of echo and the pipe.
var="$(cut -d/ -f6- <<<"$file")"
I note that you are also attempting to process the results of a find command, also with incorrect syntax. The correct syntax for this is
while IFS= read -d $'\0' -r file ; do
var="$(cut -d/ -f6- <<<"$file")"
echo "$var"
done < <(find "$1")
I must again question you as to what "field 6" is doing, since you've asked a similar question before.
Comments
Your question wasn't all that clear, but is
var=`cut -d/ -f6- < $file`
what you were after?
