PHP dynamic dropdownlists

Question

I am trying to create dynamic drop down lists in php using javascript. I am able to get the value from the dropdown list and display the second list values. However, that list gets displayed on the next page. How do i get it to display on the same page?

This is on the form page:

$(document).ready(course_selectbox_change);
function course_selectbox_change() {
    $('#course').change(update_section_list);
}

function update_section_list() {
    var course=$('#course').attr('value');
    $.get('hashtag.php?course='+course, generateSelect);
}              

function show_sections(sections) {
    $('#section').html(sections);
}



<?php
    include "database.php";
    $course= ($_REQUEST['course']);
    $semester = ($_REQUEST['semester']);

    if (isset($course)) {
        $sections = retrieveSection($course);
    }
    if (!$sections) {
        echo 'Select a course first';
    } else {
        echo '<select name="section"><option>' 
            . join('</option><option>', $sections) 
            . '</select>';
    }
?>

could you also post the generateSelect function you are calling in your $.get — DKSan
– DKSan, Commented Dec 6, 2011 at 10:11

hungneox · Accepted Answer · 2011-12-06 10:13:15Z

1

You can't use join in this case

it will print out something likes value1<option></option>value2<option></option>value3

try

<select name="section">
<?php
foreach($sections as $key => $value)
{
   echo "<option value='$key'>$value</option>";
}
?>
</select>

edited Dec 6, 2011 at 10:13

answered Dec 6, 2011 at 10:03

hungneox

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5 Comments

DKSan Over a year ago

Are you sure? I think it will output one empty option first and an unclosed one at the end. The other ones should work just fine

hungneox Over a year ago

I'm sure, it will out put exactly value1<option></option>value2<option></option>value3. Because join is alias of implode, it use <option></option> as delimeter

DKSan Over a year ago

You misread <option></option>; It is actually </option><option> and an opening <option> before the join()

DKSan Over a year ago

thats right, the closing </option> is missing after the join(); And your solution is even better to read and modify, would do it the exact same way

codingNewbie Over a year ago

i tried this but i still don't get it. it still doesn't work. The right dropdown list gets displayed but on the wrong page, and it is only after i submit the value of the first one..

the_ghost · Accepted Answer · 2011-12-06 10:20:28Z

0

Why don't to use native jquery ui autocomplete?
What do you mean by "list gets displayed on the next page"? New content appears below visible window? If "yes", just move #content block higher

answered Dec 6, 2011 at 10:20

the_ghost

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1 Comment

codingNewbie Over a year ago

when i select a course, i have to click submit before anything changes and the dropdown list which is based on this course input, gets displayed on the form action page rather than the main form page. How do i overcome that?

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