php call function within heredoc

Question

I'm trying to call a function from within a heredoc, and I read in the manual (example #2) that it is possible. However, I get the following error: Notice: Undefined property: TIME::$since on line 13.

1   <?php class TIME {
2       var $month;
3       var $year;
4       public function since($y) {
5           $this->$month = (date("F"));
6           $this->$year = (date("Y")-$y);
7           return "(since $month of $year)";
8           // return "(since date('F') of {date('Y')-$y})";
9       }
10  }
11  $time = new TIME;
12  echo <<<EOF
13      {$time->since{1}};
14  EOF; ?>

What I need to do is pass 1 as an integer to the function since() and return a string like (since January of 2011).

Have you tried renaming your class, let's say to TimeSince ? — Eugen Rieck
– Eugen Rieck, Commented Jan 11, 2012 at 14:39
And if you try {$time->since(1)} instead of {$time->since{1}} ? — Elorfin
– Elorfin, Commented Jan 11, 2012 at 14:39

Marc B · Accepted Answer · 2012-01-11 14:38:37Z

4

It's $time->since(1). Using since{1} is interpreted as "give me the 2nd character of the string stored in the $time object's attribute known as 'since'".

e.g:

$x = 'hello';
echo $x{0}; // outputs 'h'
echo $x{2}; // outputs 'l'

answered Jan 11, 2012 at 14:38

Marc B

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Comments

Timur · Accepted Answer · 2012-01-11 14:44:07Z

1

You have a lot of errors in your code. $this->$month and $this->$year must be $this->month and $this->year in your case, return "(since $month of $year)";, I think, must be return "(since {$this->month} of {$this->year})";, {$time->since{1}}; may be {$time->since(1)};, and, finally, EOF; ?> - ending PHP tag must be on newline when closing heredoc:

EOF;
?>

P.S. Why are you using old, PHP4-style properties declaration?

answered Jan 11, 2012 at 14:44

Timur

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4 Comments

Jakob Jingleheimer Over a year ago

Oh wow, that explains a lot ^^, thanks! btw, what do you mean "PHP4-style properties declaration"?

ThinkingMonkey Over a year ago

@jacob what timur is referencing to is this: var $month; check this: PHP5 Variables Basics docs

Jakob Jingleheimer Over a year ago

@ThinkingMonkey, I don't normally do that, but since I was having trouble, I tried to follow the example on the page.

Timur Over a year ago

@jacob So, I think, you now have no need to use var keyword instead of public or something else :)

KingCrunch · Accepted Answer · 2012-01-11 14:38:53Z

1

everything works like expected, but your does not have a property $since, but a method since(). Just call it like a method

$time->since(1);

Here the {1} is the alternative syntax for array access.

answered Jan 11, 2012 at 14:38

KingCrunch

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