Cannot Access PHP Object Property

Question

I'm trying to make an xmlhttp request and print out the xml. I created a class with methods and am calling those methods from an object. However, when I attempt to print the output of the method, I get nothing. I'm guessing it's something minor, but I've been trying for awhile now and have made little progress. Thanks in advance for the help.

<?php 
class twitter {

    public $screen_name;
    public $xml;
    public $count;

    public function getUserTimeline($screen_name, $count=5) {
        $request= "https://api.twitter.com/1/statuses/user_timeline.xml?include_entities=true&include_rts=true&screen_name=$screen_name&count=$count";
        return $this->makeRequest($request);
    }

    public function makeRequest($request){
        return $xml = simplexml_load_file($request);

    }

}


$test = new twitter;
$test->screen_name="mattcutts";
$test->getUserTimeline($screen_name=$test->screen_name, $count=5);
print_r($test->xml); //This does not print anything.

?>

BoltClock · Accepted Answer · 2012-02-02 05:01:52Z

4

You're creating and returning a local variable $xml here in your makeRequest() method:

    return $xml = simplexml_load_file($request);

That should simply be $this->xml:

    $this->xml = simplexml_load_file($request);

answered Feb 2, 2012 at 5:01

BoltClock

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Comments

Dinuka Thilanga · Accepted Answer · 2012-02-02 05:02:10Z

1

You try to access xml variable. But you didn't set it. You can change your method as following.

public function makeRequest($request){
    $this->xml = simplexml_load_file($request);
}

Or you can print $xml as following way.

$xmp = $test->getUserTimeline($screen_name=$test->screen_name, $count=5);
print_r($xml);

answered Feb 2, 2012 at 5:02

Dinuka Thilanga

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Comments

terenaa · Accepted Answer · 2012-02-02 05:03:53Z

-2

To create twitter object you must use constructor. So instead of $test = new twitter; use $test = new twitter();

answered Feb 2, 2012 at 5:03

terenaa

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1 Comment

BoltClock Over a year ago

$test = new twitter; is perfectly legal in PHP. The class doesn't have a constructor anyway, so whether you have the parentheses there or pass any arguments, there's no effect.

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