Fatal error: Cannot use string offset as an array
This appears when I try to find a array key by using variable array name:
class FOO {
protected $arr = array();
function bar(){
$aaaaaaaaaaaa = 'arr';
$this->$aaaaaaaaaaaa[$somekey]; // <-- error
...
}
}
How can I do this with variable array names?
@MarcinJuraszek's right, when you assign $arr the second time it's no longer an array.
Anyway, I believe this code does what you intend to
<?php
class foo
{
public function doStuff()
{
$name = 'arr';
$this->{$name} = array('Hello world!');
echo $this->{$name}[0];
}
}
$obj = new foo;
$obj->doStuff();
After that part of code:
$arr = 'arr';
$arr is no more an array. It's just a variable containing 'arr' string. So you can't access it as by key.
You should read information from PHP: Arrays - Manual.
$this->{$arr}[$somekey]
is what you want (provided that you actually assign array to $this->arr, not just $arr that you reassign later.
$arr is not an array. You first created one but then it's getting a string variable here: $arr = 'arr';.
This is correct:
$arr = array();
$arr[] = 'arr';
$somekey = 0;
$this->$arr[$somekey]
you are first defining $arr as an array, then you are OVER-writing its definition with a string. instead, maybe you wanted to add an element to the list:
$arr = array();
$somekey = 'mykey';
$arr[$somekey] = 'arrVal';
echo $arr[$somekey]
i think, i know what you want now:
a list of arrays...
$arr = array():
$arr['aaaaaaaaaa'] = array();
$arr['aaaaaaaaaa'][$somekey] = 'arrVal';
echo $arr['aaaaaaaaaaa'][$somekey]
and what's up with all the screaming?
After say
$arr = 'arr';
Variable $arr is no longer a variable, may be what you want to do is add that value to the array in which case try the following:
arr.push('arr');
Then it should work I think
