Imagine that you have to create many lines in file all with the same text except for one variable:
foo text $variable bar text
foo text $variable bar text
foo text $variable bar text
...
I was wondering if this could be made using a bash script passing it the variable as an argument:
./my_script '1'
./my_script '2'
./my_script '3'
Which would generate this:
foo text 1 bar text
foo text 2 bar text
foo text 3 bar text
Any suggestions or examples on how to do this?
See also http://tldp.org/LDP/abs/html/internalvariables.html#POSPARAMREF:
#!/bin/bash
echo "foo text ${1} bar text"
It's too trivial a task to write a script for.
Here are a couple of possible solutions:
for (( variable=1; variable<10; ++variable )); do
echo foo text $variable bar text
done
or...
for name in Dave Susan Peter Paul; do
echo "Did you know that $name is coming to my party?"
done
This might work for you:
printf "foo text %d bar text\n" {1..10}
foo text 1 bar text
foo text 2 bar text
foo text 3 bar text
foo text 4 bar text
foo text 5 bar text
foo text 6 bar text
foo text 7 bar text
foo text 8 bar text
foo text 9 bar text
foo text 10 bar text
or this:
printf "foo text %s bar text\n" foo bar baz
foo text foo bar text
foo text bar bar text
foo text baz bar text
Assuming you're stuck with that crappy template file:
perl -pe 'BEGIN {$count=0} s/\$variable/ ++$count /ge' file
This will depend on how you are getting "foo text" and "bar text". If it is set statically:
var="foo text $1 bar text"
echo "$var"
Or if it is in separate variables you can concatenate them:
foo="foo text"
bar="bar text"
output="$foo $1 $bar"
echo "$output"
cat >>output.file "foo text $1 bar text". Or can you better describe what you may really want(?)for i in {1..3}; do echo foo text $i bar text; done