Problems passing data to PHP from jQuery's AJAX

Question

im trying to pass an array of data to a PHP script using Jquery's AJAX; this is my JS:

var dataObject = {
    shippingDataRow: [{
        name: $('#shippingData_name').val(),
        street: $('#shippingData_street').val(),
        number: $('#shippingData_number').val(), 
    }]

};

$.ajax({
    type: "post",
    data: { action: 'test', data: dataObject },
    cache: false,
    url: "php/post_test.php",  
});

And this is the PHP (just doing some tests, before I can write all procedures),

<?php
    function test(){
        $dataObject = $_POST['dataObject'];
        print_r( $dataObject );
    }
?>

In Chrome's Developer Tools, I can see the Status Code:200 OK; even all the array with the correct values, but when I open the php it doesn't work.

Any ideas?

what is the value of var_dump($_POST); ?

Alex Coplan
– Alex Coplan

2012-03-05 07:25:42 +00:00
Commented Mar 5, 2012 at 7:25 — Alex Coplan
– Alex Coplan, Commented Mar 5, 2012 at 7:25
Your code contains un-necessary commas, IE WILL complain!

Salman Arshad
– Salman Arshad

2012-03-05 07:42:47 +00:00
Commented Mar 5, 2012 at 7:42 — Salman Arshad
– Salman Arshad, Commented Mar 5, 2012 at 7:42

Billy Moon · Accepted Answer · 2012-03-05 07:26:11Z

1

try: $dataObject = $_POST['data'];

You need to refer to the key of the posted data, not the value in javascript.

answered Mar 5, 2012 at 7:26

Billy Moon

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Comments

Muhammad Zeeshan · Accepted Answer · 2012-03-05 07:26:48Z

0

Your post should be

$_POST['data'];

answered Mar 5, 2012 at 7:26

Muhammad Zeeshan

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Comments

sandeep · Accepted Answer · 2012-03-05 07:28:55Z

0

You are not calling test().in anywhere.so,its cuess return 200ok but response null.echo anything in test_php.and check.

answered Mar 5, 2012 at 7:28

sandeep

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adeneo · Accepted Answer · 2012-03-05 07:31:22Z

0

var dataObject = {
    shippingDataRow: {
        name: $('#shippingData_name').val(),
        street: $('#shippingData_street').val(),
        number: $('#shippingData_number').val()
    }
};

$.ajax({
    type: "post",
    data: { action: 'test', data: dataObject },
    cache: false,
    url: "php/post_test.php"
});

-

<?php
   $dataObject = $_POST['data'];
   print_r( $dataObject );
?>

answered Mar 5, 2012 at 7:31

adeneo

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Comments

francisco.preller · Accepted Answer · 2012-03-05 07:32:47Z

0

As others mentioned, $_POST['data'] will get you the data array.

Also, using $_REQUEST works well as it'll target both get/post requests.

answered Mar 5, 2012 at 7:32

francisco.preller

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Comments

Emil · Accepted Answer · 2012-11-14 09:46:29Z

0

Change:

$dataObject = $_POST['dataObject'];

To:

$dataObject = $_POST['data'];

edited Nov 14, 2012 at 9:46

Emil

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answered Mar 5, 2012 at 7:25

Sudhir Bastakoti

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