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Is it possible to append a parameter to a PHP Header Location? I'm having trouble getting it to work. Is this syntax actually allowed?

$qry = $_SERVER['QUERY_STRING'];
header('Location: http://localhost/blast/v2/?$qry ') ;

it just won't replace $qry wit its actual value....why??

in the browser it ends up looking like this:

http://localhost/blast/v2/?$qry

thanks

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4 Answers 4

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Important note: do not use this exactly if you cannot be sure that $qry is safe!

Change the single quotes to double quotes:

header("Location: http://localhost/blast/v2/?$qry");

A single quoted string in PHP is treated as a string literal, which is not parsed for variables.

Double quoted strings are parsed for variables, so you will get whatever $qry contains appended, instead of literally $qry.

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3 Comments

I try this one header("Location:http://example.com/file.php?id=$ID"); but the header() adds a /at the end of $ID and making it a directory. That is it riderects to http://example.com/file.php?id=5/(Note the / at the end) Please give a solution
Post a new question explaining your problem in detail. Don't hijack a post's comments
Great explanation @Bojangles. For people reading this, you may also have heard the term "string interpolation," which is what's happening here.
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You can also add multiple parameters via a header like:

$divert=$row['id']."&param1=".($param1)."&param2=".($param2);
header("Location:showflagsab.php?id=$divert");

which adds the two additional paramaters to the original id

These can be extracted using the $get method at their destination

1 Comment

Mr.Howard.. I need your help in your ans code..your ans will send single record but incase if there are some duplicate records than how to store that in other page.?
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I know this is a very old post, but please, do not do this. Parameters in a header are XSS vulnerable. You can read more about XSS'ing here: owasp.org/index.php/Cross-site_Scripting_(XSS)

Comments

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wiles How to Fix the XSS attack on header location

$param = $_REQUEST['bcd'];
header("Location: abc.php/?id=$param");

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