Sending json data to php web service

Question

I am sending to the server this call:

var Message = {};
Message['islands'] = '1-15-13';
Message['newMessageText'] = 'this is test message';
$.ajax({
    url: "sendnote.php",
    type: "POST",
    data: Message,
    dataType: "json",
    contentType: "charset=utf-8",
    success: function (data) {
        alert(data["result"]);
    },
    error: function (data) {
        alert(data["result"]);
    }
});

and on server (sendnote.php) I have

print_r($_POST);

just to check do I receive anything, but after cchecking response in Firebug I see that this array is empty.

What am I doing wrong in sending data?

Thanks in advance!

PS I've checked previous post on this subject, but still have problems with it.

Hmm, how did you get data["result"]? Is there more to the sendnote.php script that you are not showing? Or is it just print_r($_POST)? — Gohn67
– Gohn67, Commented Mar 27, 2012 at 6:27
Quentin, you are right, I see that too, but in Firebug I see that my $_POST is empty. That's the problem. That's why I did just print_r($_POST) — Draško
– Draško, Commented Mar 27, 2012 at 7:14

jivetek · Accepted Answer · 2012-03-27 08:03:05Z

1

The problem is the contentType

Try this:

jQuery

$(document).ready(function(){
var Message = {};
    Message['islands'] = "1-15-13";
    Message['newMessageText'] = 'this is test message';

$.ajax({
        url: "sendnote.php",
        type: "POST",
        data: Message,
        dataType: "json",
        success:function(data) {
            alert("Islands: "+data.islands+", Message: "+data.newMessageText);
            },
        error:function(data) {
            alert('error');
        }  });
});

php

<?php
    echo json_encode($_POST);
?>

answered Mar 27, 2012 at 8:03

jivetek

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Comments

Joseph · Accepted Answer · 2012-03-27 07:27:53Z

1

print_r($_POST) does not give a JSON response. do you even know what the actual reply of the request looks like when not using AJAX?

try echo json_encode($_POST); - this should print out a valid JSON.

or might i add that you might have forgotten PHP's <?php ?> opening and close tags

edited Mar 27, 2012 at 7:27

answered Mar 27, 2012 at 6:26

Joseph

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2 Comments

Gohn67 Over a year ago

I think he's checking the ajax request in Firebug. But yeah, I think you are right if sendnote.php is just print_r($POST);

Draško Over a year ago

Gohn67, you are right. I am just checking $_POST in Firebug. I have in my code $jsonresponse = json_encode($_POST) and other code which creates JSON response. On the client side I receive JSON response that is obviously result of empty $_POST.

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