Push first object to last in javascript array keeping all other values intact

Question

I have the following JavaScript array :

 var days = [
            {
                "day": "sunday",
                "morning": "geschlossen",
            },
            {
                "day": "monday",
                "morning": "geschlossen",
            },
            {
                "day": "tuesday",
                "morning": "geschlossen",
            },
            {
                "day": "wenesday",
                "morning": "geschlossen",
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr",
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr",
            },
            {
                "day": "saturday",
                "morning": "geschlossen",
            }
        ];

How can i change the 0th index object to last value in the array?

so my expected array will be like this :

 var days = [               
            {
                "day": "monday",
                "morning": "geschlossen",
            },
            {
                "day": "tuesday",
                "morning": "geschlossen",
            },
            {
                "day": "wenesday",
                "morning": "geschlossen",
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr",
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr",
            },
            {
                "day": "saturday",
                "morning": "geschlossen",
            }, 
            {
                "day": "sunday",
                "morning": "geschlossen",
            }
        ];

I played around with splice and pop, but not getting anywhere intended.

IvanH · Accepted Answer · 2013-11-13 10:51:56Z

6

Use javascript shift and push function push function adds the element in last and shift function removes and returns the first element

days.push(days.shift());

edited Nov 13, 2013 at 10:51

IvanH

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answered Nov 13, 2013 at 10:28

Sikander

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Comments

lonesomeday · Accepted Answer · 2013-11-13 10:23:13Z

6

You need to remove the element from the beginning of the array. Array#shift does this. Then you need to add that element to the end of the array. Array#push does that. Since shift returns the element shifted, you can do it in one call:

days.push(days.shift());

The key functions for affecting the first and last elements of an array are:

shift: remove an element from the beginning of the array
unshift: add an element to the beginning of the array
pop: remove an element from the end of the array
push: add an element to the end of the array

answered Nov 13, 2013 at 10:23

lonesomeday

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1 Comment

Roy M J Over a year ago

Thankyou.. Worked perfectly.. Since all of you posted the same answer, i accepted the one with the lowest reputation..

pax162 · Accepted Answer · 2013-11-13 10:20:50Z

5

How about this:

days.unshift(days.pop())

EDIT, after op edit:

days.push(days.shift())

answered Nov 13, 2013 at 10:20

pax162

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2 Comments

Roy M J Over a year ago

I want the popped out 0th index to be inserted at the last...:(

pax162 Over a year ago

:) In cases like these, accept the answer from the guy(or gal) with the lowest reputation.

Kris · Accepted Answer · 2013-11-13 10:44:47Z

Try this (not tested) :

var days= [
            {
                "day": "sunday",
                "morning": "geschlossen"
            },
            {
                "day": "monday",
                "morning": "geschlossen"
            },
            {
                "day": "tuesday",
                "morning": "geschlossen"
            },
            {
                "day": "wenesday",
                "morning": "geschlossen"
            },
            {
                "day": "thursday",
                "morning": "16:30 - 19:00 Uhr"
            },
            {
                "day": "friday",
                "morning": "09:00 - 18:00 Uhr"
            },
            {
                "day": "saturday",
                "morning": "geschlossen"
            }
        ];


var first = days[0];
days.shift();
days.push(first);
console.log(days);

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