How to push item into array without removing last element

Question

when sameFriends = [];

'dick', 'rex', 'james' gets push in

when I added 'golf', //output remove james

How can I add push in the same element from aFriend and bFriend without removing any?

let aFriend = ['dick', 'rex', 'james', 'tom', 'jack'];
let bFriend = ['dick', 'rex', 'james', 'jake'];
let sameFriend = ['golf'];

for (let i = 0; i < aFriend.length; i++){
  for (let k = 0; k < bFriend.length; k++){
    if (aFriend[i] === bFriend[k]){
      sameFriend.push(bFriend[k]);
      console.log(sameFriend[k]);
    }
  }
}

Your code although can be bettered but works correctly. I see this output : ["golf","dick","rex","James"]. What do you expect? — Tushar Shahi
– Tushar Shahi, Commented Jun 25, 2021 at 9:44
console.log(sameFriend[k]); The index k is for array bFriend not sameFriend witch is not the same size... — A.Baudouin
– A.Baudouin, Commented Jun 25, 2021 at 9:48
You can do this with one line : console.log(sameFriend.concat(aFriend.filter(item => bFriend.indexOf(item) >= 0))); — A.Baudouin
– A.Baudouin, Commented Jun 25, 2021 at 9:53

mk23 · Accepted Answer · 2021-06-28 11:35:05Z

1

You can use code as below:

let aFriend = ['dick', 'rex', 'james', 'tom', 'jack'];
let bFriend = ['dick', 'rex', 'james', 'jake'];
let sameFriend = ['golf'];

for (let i = 0; i < aFriend.length; i++){
    for (let k = 0; k < bFriend.length; k++){
        if (aFriend[i] === bFriend[k]){
        sameFriend.push(bFriend[k]); //Here sameFriend array will have all elements which are same
       // console.log(sameFriend);
        }
    }
}
console.log(sameFriend);

edited Jun 28, 2021 at 11:35

answered Jun 25, 2021 at 9:44

mk23

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1 Comment

mk23 Over a year ago

Thanks @FZs just reread the details and updated code to reflect the desired output.

Akhila · Accepted Answer · 2021-06-25 16:34:07Z

1

Method 1: Change

console.log(sameFriend[k]);

To

console.log(bFriend[k]);

and add

console.log(sameFriend);

before entering 'for loop'.

The element you push into sameFriend is not stored at kth index of it. That is why James didn't get printed.

Method 2:

Remove the console statement inside the 'for loop' and add

console.log(sameFriend);

at the end of the code to print all elements of sameFriend

edited Jun 25, 2021 at 16:34

answered Jun 25, 2021 at 9:59

Akhila

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2 Comments

Kim Over a year ago

I want it to print the similar names in aFriend and bFriends and including the element in sameFriend. That's why I'm using .push()

Akhila Over a year ago

Either You can print the elements of sameFriend before 'for loop' and then proceed with 'for loop' with change I have mentioned OR add "console.log(sameFriend)" at the end of the code and remove console statement inside the 'for loop'.

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