How to add numbers to an array in form of strings?

Question

My Question is following: Given a number n as input, return a new string array of length n, containing the strings “0″, “1″, “2″ so on till n-1. If n=0, return an array of length 0.The expected output is- stringArray(4) = {"0","1","2","3"} and the actual output is stringArray(4) = {0,1,2,3}.How can I add numbers in the form of string.

public class ArrayOfNumbers {

    static int testcase1=4;

    public static void main(String[] args){
        ArrayOfNumbers testInstance=new ArrayOfNumbers();
        String[] result=testInstance.arrayOfNumbers(testcase1);
        System.out.print("{");
        for (int i=0;i<result.length;i++){
            if (i>0)
                System.out.print(",");
            System.out.print(result[i]);
        }
        System.out.println("}");
    }

    public String[] arrayOfNumbers(int num) {
        int n=0;
        String n1="n";
        String[] arr=new String[num];
        for(int i=0;i<num;i++){
            arr[i]=n1;
            n=n+1;
        }
        return arr;
    }
}

Are you asking how to include " marks when you print each number? — Dawood ibn Kareem
– Dawood ibn Kareem, Commented Apr 1, 2014 at 20:36
You can use String.valueOf() to parse a number to a string. — Steffen
– Steffen, Commented Apr 1, 2014 at 20:40

Elliott Frisch · Accepted Answer · 2014-04-01 20:40:57Z

2

Change your arrayOfNumbers method,

public String[] arrayOfNumbers(int num) {
    String[] arr = new String[num];
    for (int i = 0; i < num; i++) {
        arr[i] = "\"" + String.valueOf(i) + "\"";
    }
    return arr;
}

Then, you could use

String[] result = testInstance.arrayOfNumbers(testcase1);
System.out.println(Arrays.toString(result));

Or (to match your output exactly) use your existing main.

answered Apr 1, 2014 at 20:40

Elliott Frisch

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2 Comments

Anthony Raymond Over a year ago

i don't think he want to sourround his number with " ", but adding String to the array.

Elliott Frisch Over a year ago

@AnthonyRaymond Take another look at the expected output (compared to the actual output). Obviously, I might be wrong... I have been before, and I'm sure I will be wrong again (I just don't think I am here).

Anthony Raymond · Accepted Answer · 2014-04-01 20:44:57Z

2

public String[] arrayOfNumbers(int num) {
    String[] arr=new String[num];
    for(int i=0;i<num;i++){
        arr[i]="\"" + i + "\"";
    }
    return arr;
}

edited Apr 1, 2014 at 20:44

answered Apr 1, 2014 at 20:37

Anthony Raymond

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2 Comments

resueman Over a year ago

Also, he can get rid of n, and just use 'i' in it's place.

Anthony Raymond Over a year ago

Add the solver marker to your post then :) Click on the cross on the left of an answer

M Abbas · Accepted Answer · 2014-04-01 20:36:43Z

1

for (int i=0;i<result.length;i++){
    if (i>0)
        System.out.print(",");
    System.out.print("\"" + result[i] + "\"");
}

answered Apr 1, 2014 at 20:36

M Abbas

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