Java array input thorughnextInt()

Question

 import java.util.*;;

    public class selection {
    Scanner in=new Scanner(System.in);
    private int size;
    private int[] num=new int[size];

    selection(int size){
      this.size=size;
             }
    void enternum(){
        System.out.print("enter number"+size);
        for (int i=0;i<5;i++)
            num[i]=in.nextInt();

    }

    void sort(){
        for (int i=0;i<num.length;i++){
        int min=i;

        for(int j=i+1;j<num.length;j++){

                if(less(num[i],num[j]))
                    excg(i,j);
        }
    }

     display();

    }

    boolean less(int x,int y){
        if(x>y)
            return true;
        else
            return false;

    }

    void excg(int i,int j){

        num[i]=num[j];
        num[j]=num[i];
    }


    void display(){
        for(int i=0;i<num.length;i++)
            StdOut.println(num[i]);
    }

 public static void main (String[] arg){
        Scanner in=new Scanner(System.in);
       System.out.print("enter total num of the array");
        int size=in.nextInt();

        selection obj=new selection(size);
        obj.enternum();
        obj.sort();
    }
 }

when we enter the direct value of the size i.e size=5 then it is working but whenwe enter throughkey board then it is giving error aaray out of box .i am taking input through scanner class using nextInt() method

Paul Hicks · Accepted Answer · 2014-04-04 09:38:23Z

1

That's because you allocate the array to be size 0. If you allocate it after you read in the size, instead of before, then it'll work.

answered Apr 4, 2014 at 9:38

Paul Hicks

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Subhrajyoti Majumder · Accepted Answer · 2014-04-04 09:39:32Z

1

Initilize the array at the constructor. By deafult int class member(size) initialized with 0.

private int[] num;

selection(int size){
    //this.size=size;  //not required. 
    num=new int[size];
}

answered Apr 4, 2014 at 9:39

Subhrajyoti Majumder

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