nextInt stored inside an array Java

Question

So I have this this code:

int[] player1 = new int[5]; // first player
            try{

               for(int i=0;i<5;i++) {

                   player1[i] = keyin.nextInt();}
               }
           catch(NumberFormatException e){

               System.out.println("Player 2 : ")

           }
int[] player2 = new int[5]; // Second Player

                try{

               for(int i=0;i<5;i++) {

                   player2[i] = keyin.nextInt();}
               }
           catch(NumberFormatException e){

               System.out.println("Player 3 : ");  
           }

I'm trying to get the user to input 5 or less integers for betting purposes, but somehow my code keeps forcing the user to input 5 orelse it won't catch and go to the second player.. How do I change this?

nextInt should be followed by nextLine to remove the carriage return which still remains within the System.in buffer...otherwise nextInt will fail the next time it is called — MadProgrammer
– MadProgrammer, Commented Feb 12, 2015 at 0:33
@MadProgrammer How would I write that exactly? (Newbie coder!) — X1XX
– X1XX, Commented Feb 12, 2015 at 1:32

freddiev4 · Accepted Answer · 2015-02-12 00:34:31Z

2

You're using a for loop to request that the user inputs 5 numbers

for(int i=0;i<5;i++) {

                   player1[i] = keyin.nextInt();}
               }

This is saying that the user must input a number until i increments itself to 5, meaning 5 inputs.

What you could do is make a while loop saying:

while(keyin.hasNextInt()){

}

And then use an if statement that breaks out of the loop once the input reaches 5 characters, or if the user breaks out of the loop by pressing a key on the keyboard.

answered Feb 12, 2015 at 0:34

freddiev4

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2 Comments

X1XX Over a year ago

I'm trying to make it so the user only has to press anything else but an int it has to look like Player1: 1 2 3 4 and on the following line Player2: 3 2 1

X1XX Over a year ago

I would put the while loop outside the for loop?

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