How to grab specific part of url in AngularJs

Question

My Url looks like : www.ccadmin/admin.jsp?id=Aetna834

How to grab Aetna834

possible duplicate of How to get the value from URL Parameter? — Patrick Reck
– Patrick Reck, Commented Sep 25, 2014 at 15:36

Tom A · Accepted Answer · 2014-09-25 15:44:54Z

1

You can do it in plain JS, or you can use the $location service, which is a little easier IMO. "Aetna834" would be found using:

$location.search().id

answered Sep 25, 2014 at 15:44

Tom A

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