How to use get part in url with angular

Question

The situation is the Oauth server will redirect to my site with this url:

$location.absUrl():http://abcdefg.com/?code=0415fca7f0b126554c768d8fafcba1eL&state=STATE#/wechat

However, the result of the $location.search().code is undefined

So, I want a correct way to get the code part of the URL.

what is the result of $location.search()? (to see if code is trying to access an empty object, if it has state, etc) — Sze-Hung Daniel Tsui
– Sze-Hung Daniel Tsui, Commented May 25, 2015 at 8:39

rahlrokks · Accepted Answer · 2015-05-25 08:40:33Z

1

You can use $location.search().code get the value from query string.

answered May 25, 2015 at 8:40

rahlrokks

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2 Comments

UNSTABLE Over a year ago

However, the result of the $location.search().code is undefined

UNSTABLE Over a year ago

See my post, the result is undefined,Only this way $location.search().code can get the value: abcdf.com/#/…

Sze-Hung Daniel Tsui · Accepted Answer · 2015-05-25 08:52:02Z

0

Try taking taking $location string, finding the '=' index with indexOf, and splicing the code from index+1 (to skip the '=') to indexOf('&'). It's a little dirty, but could get you on your way.

answered May 25, 2015 at 8:52

Sze-Hung Daniel Tsui

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