I'm trying to make list contain (even numbers) with using while loop :
a=0
while a<8:
a=a+2
print(a,end=' ')
t=list(a)
print (t)
and how do I can make a code to division the numbers from the first list into two list: one for(even numbers) and the other for (odd numbers) ?
Use list to convert.
In [1]: a=(1,2,3)
In [2]: list(a)
Out[2]: [1, 2, 3]
In [3]: b=('City')
In [4]: list(b)
Out[4]: ['C', 'i', 't', 'y']
You can just create a list directly from each variable
>>> a = list(a)
>>> a
[1, 2, 3]
>>> b = list(b)
>>> b
['C', 'i', 't', 'y']
To make a list of even numbers using a while loop, you can do something like this
a = 0
t = []
while a < 8:
t.append(a)
a += 2
>>> print(t)
[0, 2, 4, 6]
Note that the above is just for learning purposes, this can be done using Python's range function more easily
>>> list(range(0, 8, 2)) # Evens
[0, 2, 4, 6]
>>> list(range(1, 8, 2)) # Odds
[1, 3, 5, 7]
Here is my answer to your question:
List = []
ListEven = []
ListOdd = []
Count = 0
while(Count < 11):
print(Count, end = ' ')
List.append(Count)
if(Count % 2 == 0):
ListEven.append(Count)
elif(Count % 2 != 0):
ListOdd.append(Count)
Count += 1
print("\n""This is the main list:")
print(List)
print("This is the even list:")
print(ListEven)
print("This is the odd list:")
print(ListOdd)
I fixed the Count from Count += 2 to Count += 1 because you asked for a list of odds. The code you had would only produce even numbers. I hope this helped answer your question. :)
