How to implement a while loop in Python?

Question

Basically I need to write a program that takes input from a user and stores it in a list over and again until the word "end" is passed.

Sample Input

Spanish
dog
bowl
end

Sample Output

['spanish', 'dog', 'bowl']

This is what I have so far:

a = []
index = 0
i = 1
while i != 0:
    s = raw_input()
    if s == "end":
        i = 0
    else:
        a[index] = s
        index = index + 1
print (a)

Note that as part of the assignment, a while loop must be used.

Do you really need all the commentary about the teacher to ask this question? — Cory Kramer
– Cory Kramer, Commented Mar 31, 2020 at 14:08
I suppose i didn't need to include that no, my bad. Just in a bit of a hurry so wasn't thinking. Thanks for the answer! — MossDog
– MossDog, Commented Mar 31, 2020 at 14:30

Cory Kramer · Accepted Answer · 2020-03-31 14:11:01Z

4

words = []
while True:
    word = input()
    if word == 'end':
        break
    else:
        words.append(word)
print(words)

Example

Spanish
dog
bowl
end
['Spanish', 'dog', 'bowl']

answered Mar 31, 2020 at 14:11

Cory Kramer

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Comments

Ma0 · Accepted Answer · 2020-03-31 14:10:25Z

1

If you are using Python 3.8+, you can use this cool new feature called assignment expressions like so:

lst = []
while (answer := input('item (type "end" to exit): \t')) != 'end':
    lst.append(answer)
print(lst)

answered Mar 31, 2020 at 14:10

Ma0

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Comments

kederrac · Accepted Answer · 2020-03-31 14:49:14Z

0

if you like one-line solution:

from itertools import takewhile, cycle

words = list(takewhile(lambda x: x != 'end', map(input, cycle(['type your item: ']))))

or:

words = list(takewhile(lambda x: x != 'end', map(input, cycle(['']))))
print(words)

output:

Spanish
dog
bowl
end
['Spanish', 'dog', 'bowl']

answered Mar 31, 2020 at 14:49

kederrac

17.4k6 gold badges36 silver badges58 bronze badges

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