URLEncoder: encoding string in android

Question

I am constructing String in my android app and then pass it to URLEncoder.

String searchStr;
// then I get some searchStr from shared preferences
// i check it is correct
searchStr = searchStr + "/page/"+pageNumber+"";

Then I pass that searchStr to URL encoder:

try {
  String url_params = URLEncoder.encode(params[0]);
  String result = downloadURL("some url/" + url_params);
  Log.d("key", url_params); // -> php/page/10
}catch (IOException){
  Log.d("key", e.getMessage() );
}

So here i get IOException which shows me this message:

http://some url/php%2Fpage%2F10

If I copy paste it to browser it shows me Not found error with this message:

The requested url  someurl/php/page/10 was not found on this server

Also if I change those strange sign %2F into / in browser I am able to get the page. So how can I construct proper string with / instead of %2F sign?

See stackoverflow.com/questions/10786042/… . In your case you should probably just encode the page number (if it may contain special chars) or skip encoding altogether. — headuck
– headuck, Commented Sep 27, 2015 at 15:17

Bhavdip Sagar · Accepted Answer · 2015-09-27 14:56:12Z

2

You don't encode the entire URL, only parts of it that come from "unreliable sources".

String query = URLEncoder.encode("apples oranges", "utf-8");
String url = "http://stackoverflow.com/search?q=" + query;

answered Sep 27, 2015 at 14:56

Bhavdip Sagar

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