I want to use the URLEncoder/URLDecoder class (java.net.URLEncoder/URLDecoder) in an application and the methods : encode(String s, String enc)/decode(String s, String enc), but I don't know what can be the value of the String argument enc? I want to encode/decode in the "x-www-form-urlencoded" MIME content type. Thank you for your help.
Add a comment
|
5 Answers
The encoding parameter is the character encoding you're using. For example "UTF-8".
4 Comments
Michaël
So I have to write it like that : encode("hello","x-www-form-urlencoded") or for "x-www-form-urlencoded" it's encode("hello","UTF-8")?
jgre
You have to write encode("hello","UTF-8"). x-www-form-urlencoded is always the type of the result. The encoding parameter refers to your input data.
Janusz
Is there a predefined constant for the possible character encodings?
Someone Somewhere
android documentation is SO bad! URLEncoder class documentation doesn't even mention "UTF-8" developer.android.com/reference/java/net/URLEncoder.html
First you need to set the content-type as a 'x-www-form-urlencoded'. Then whatever content you would like to encode, encode it using "UTF-8".
For example:
For setting content to 'x-www-form-urlencoded':
URL url = new URL("http://www.xyz.com/SomeContext/SomeAction"); <br>
URLConnection urlConnection = url.openConnection();<br>
....<br>
....<br>
urlConnection.setRequestProperty("Content-type","application/x-www-form-urlencoded");
Or if you are using some JSP then you can write the following on top of it.
<%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8" %><br>
< META http-equiv="Content-Type" content="text/html; charset=UTF-8">
< FORM action="someaction.jsp" enctype="application/x-www-form-urlencoded" name="InputForm" method="POST">
And to use URLEncoder:
String encodedString = URLEncoder.encode("hello","UTF-8");
2 Comments
Michaël
I have done : - HttpPost post = new HttpPost("url"); - post.setHeader("Content-Type", "application/x-www-form- urlencoded"); - String encodedString = URLEncoder.encode("hello","UTF-8"); - StringEntity temp; - temp.setContentEncoding(encodedString); - post.setEntity(temp); and then execute a DefaultHttpClient with post for argument.
Michaël
The problem was really due to the fact that I put "application/x-www-form-urlencoded" instead of "UTF-8" in encode(String s, String enc)... Again thank you.
The JavaDoc has all the details
answered May 22, 2009 at 7:36
Thilo-Alexander Ginkel
6,97810 gold badges48 silver badges59 bronze badges
1 Comment
fIwJlxSzApHEZIl
The JavaDoc doesn't mention all of the possible encoding formats nor do I see a link to an ENUM which might list them.
URLEncoder and URLDecoder both are exception Throwable and thus must be at least enclosed by try/catch block. However there is a litle bit simplier way using android.net.Uri:
Uri.decode(string);
Uri.encode(string);
Those are static methods, uses utf-8, available since API-1 and throws no exception.
Comments
My personal favourite:
static String baseNameFromURL(URL url) {
String shortName;
String path = url.getPath();
String escaped = path.substring(path.lastIndexOf('/') + 1);
try {
shortName = URLDecoder.decode(escaped, "UTF-8");
} catch (UnsupportedEncodingException e) {
throw new Error(e.getMessage(), e);
}
int period = shortName.lastIndexOf('.');
return period > -1 ? shortName.substring(0, period) : shortName;
}
Returns an empty String if the URL doesn’t have a file name part, like https://stackoverflow.com/ or https://stackoverflow.com/questions/. If there is a backslash in the file name part, it is conserved.
You may strip off the last two lines if you need the short name with extension instead.
