php if expression using regex

Question

im trying to get any input-ed data to be replaced by the value '7', if it is not a number between 0 and 9.

Here's my code atm:

echo "Enter no. of days to search: ";
$handle = fopen ("php://stdin","r");
$days = fgets($handle);

$days2 = str_replace("\n", '', $days);

if ($days2 == '/^[0-9]{1}$/'){
    $days2 = "7";}

it doesnt replace any input (letters or numbers) with 7 though! Help please! Thanks

Edit:

if ($days2 >= 0 && $days2 <= 9){
    }
else $days2 = "7";

works but only for numbers outside the range, not for if i input letters

Hey there will! Unfortunately this syntax is not right. You need to use php.net/manual/en/function.preg-match.php and/or php.net/manual/en/function.preg-replace.php — Mikel Bitson
– Mikel Bitson, Commented Oct 29, 2015 at 15:30

Nirnae · Accepted Answer · 2015-10-29 15:34:51Z

3

<?php
 if (!is_numeric($days2) || $days2 > 9 || $days2 < 0){
     $days2 = "7";
 }
?>

This might be what you're looking for, without using any regex

answered Oct 29, 2015 at 15:34

Nirnae

1,34511 silver badges23 bronze badges

Sign up to request clarification or add additional context in comments.

3 Comments

Nirnae Over a year ago

No prob, dont forget to put your question as resolved ;)

chris85 Over a year ago

@will meta.stackexchange.com/questions/23138/…

Nirnae Over a year ago

just click the "check" symbol on the left of my answer

Collectives™ on Stack Overflow

php if expression using regex

1 Answer 1

3 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

3 Comments

Your Answer

Sign up or log in

Post as a guest

Related