Access property of a class in typescript via string for sort

Question

The problem is simple, in javascript I can have an object as this one

var obj={
    par1:'value1',
    par2:'value2'
}

And I can access to the values in this ways obj['par1'] is it possible to do the same thing in TypeScript with a class like this:

export class obj{
    par1:string;
    par2:string;
}

this.obj['par1']=value1

Update

This is the Documents class

export class Documents {
    par1: string
    par2: string
    constructor(par1: string,
        par2: string
    ){
        this.par1=par1
        this.par2=par2
    }
}

And this is my attempt:

private docs:Documents[]=new Documents[
    new Documents('value1','value2'),
    new Documents('value3','value4')
];
sort(ordertype:string,property:string){
    for(let doc of this.docs){
        for(let field in doc)
            console.log(doc[field])
    }
}

And this is an error:

[ts] Element implicitly has an 'any' type because index expression is not of type 'number'.

I've even tried to cast it to string but nothing.

Update 2

I've saw the error, I corrected it, the code above is correct and works.

Ok sorry it was a generic question, in attempt to get some information on typescript and understand the difference between the javascript objects an typescript classes — mautrok
– mautrok, Commented Jul 26, 2016 at 13:58

Nitzan Tomer · Accepted Answer · 2016-07-26 15:07:55Z

2

You don't create the Documents array properly, it should be like this:

let docs: Documents[] = [];
docs.push(new Documents('value1', 'value2'));
docs.push(new Documents('value3', 'value4'));

or

let docs: Documents[] = [new Documents('value1', 'value2'), new Documents('value3', 'value4')];

If you do that then your code works fine, check it out in playground.

answered Jul 26, 2016 at 15:07

Nitzan Tomer

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Comments

Bruno Grieder · Accepted Answer · 2016-07-26 15:00:54Z

0

Try replacing console.log(doc[field]) with console.log((doc as any)[field])

answered Jul 26, 2016 at 15:00

Bruno Grieder

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