Showing maximum value of an object in an array when it as two max values

Question

I have an array from the api response and its objects.I need to find the value which has maximum total and I have display it I'm unable to solve it , when there are two max values of the total.Is there any solution?

myArray[
{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}
];

I tried reduce function like this:

var data =[];
data.reduce((max, p) => p.total > max ? p.total : max, data[0].total);

What do you mean by 'when there are two max values of the total'? — Cata John
– Cata John, Commented Mar 14, 2018 at 6:54
What do you want to display when there are two maximums? Both or either one or the earlier one or the later one? What if there are three, four? Or do you just need the max total value? — Aydin4ik
– Aydin4ik, Commented Mar 14, 2018 at 6:56
I need to display the time of when two objects has same highest 'total' value. — Hema Nandagopal
– Hema Nandagopal, Commented Mar 14, 2018 at 6:57

Community · Accepted Answer · 2020-06-20 09:12:55Z

2

You can do something like this:

Idea:

Create a hashMap with total as keys and a variable to hold max value.
Check if the key exists and if not, initialize it to an array.
Push current object in this array.
Fetch the array with the key as max and you will get all the values with max total.

Now that you have entire object, you can iterate and display any necessary values.

var myArray = [{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}]

var max = 0;
var hashMap = myArray.reduce((acc, p) => {
  max = Math.max(max, p.total);
  acc[p.total] = acc[p.total] || [];
  acc[p.total].push(p);
  return acc;
}, {});

console.log(hashMap[max]);

With only time value

var myArray = [{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}]

var max = 0;
var hashMap = myArray.reduce((acc, p) => {
  max = Math.max(max, p.total);
  acc[p.total] = acc[p.total] || [];
  acc[p.total].push(p.time);
  return acc;
}, {});

console.log(hashMap[max]);

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Mar 14, 2018 at 7:01

Rajesh Dixit

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2 Comments

Hema Nandagopal Over a year ago

Instead of getting the full object,Can you help to get the 'time' alone?

Rajesh Dixit Over a year ago

Kindly check the update. Though I prefer getting entire object. This way, its more flexible.

Faly · Accepted Answer · 2018-03-14 06:54:45Z

1

You can use Math.max along with spread and array.prototype.map:

var myArray = [
{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}
];

var max = Math.max(...myArray.map(e => e.total));

console.log(max);

answered Mar 14, 2018 at 6:54

Faly

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Comments

Cata John · Accepted Answer · 2018-03-14 07:03:01Z

0

You can find the maximum 'total' value in the array and then find all the elements of the array with that maximum value.

var myArray = [
{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}
];

var max = Math.max(...myArray.map(e => e.total));
var time = myArray.filter(item => item.total == max);

console.log(time);

answered Mar 14, 2018 at 7:03

Cata John

1,40112 silver badges20 bronze badges

1 Comment

Rajesh Dixit Over a year ago

You are looping twice. You can achieve this in same loop. Feel free to refer to my answer.

guijob · Accepted Answer · 2018-03-14 07:06:50Z

0

One possible approach:

function getMaxValue(myArray) {
    var totals = myArray.map(x => x.total);
    var max = filter(x => x == Math.max(totals));
    return max.length == 1 ? max[0] : 'unable to solve it';
}

answered Mar 14, 2018 at 7:06

guijob

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Showing maximum value of an object in an array when it as two max values

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Idea:

With only time value

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Idea:

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