i have string like this:
string = "The stock item "28031 (111111: Test product)" was added successfully."
I need store from string the first 5 numbers ( for example "28031" ) and save them to another string.
It's because i am selenium tester and every time i am create new stock item he has different first 5 numbers.
Thank you for your help
Filip
m = re.search("\d+", string)
print m.group(0)
prints 28031
It just selects the first group of digits, regardless of the length (2803 would be selected, too)
Firstly I am assuming all these strings have exactly the same format. If so the simplest way to get your stock item number is:
stocknumber = string.split()[3][1:]
After sehe answer I leave mine edited just to show how to match 5 digits
import re
re.search('\d{5}', string).group(0)
EDIT : neurino solution is the smartest!! use it
EDIT : sehe solution is smart and perfect you can add this line to get only the first 5 numbers:
print m.group(0)[0:5]
using [0:5] means to take string elements from 0 to 5 (first 5 elements)
use the str.isdigit built-in function
string = "The stock item 28031 "
Digitstring=''
for i in string:
if i.isdigit():
Digitstring+=i
print Digitstring
Output:
28031
you can count to first x numbers you need and then stop.
