$.isArray() function some problems

Question

I wanted if the arr is true alert true if not alert false. Where I actually making mistake I checked my code at jslint but I found only alert was used before it was defined. Thank you

var arr = [1,23,4,5];
if(arr.isArray()===-1){
 alert(' false ');
}else{
  alert(' true ');
}

Felix · Accepted Answer · 2014-05-15 03:44:54Z

1

You need to use:

if(!$.isArray(arr)){

instead of:

if(arr.isArray()===-1){

since $.isArray() take an argument which is an object to determine whether that object is an array or not:

var arr = [1, 23, 4, 5];
if (!$.isArray(arr)) {
    alert(' false ');
} else {
    alert(' true ');
}

Fiddle Demo

answered May 15, 2014 at 3:44

Felix

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Comments

Dinuka Thilanga · Accepted Answer · 2014-05-15 03:43:14Z

0

isArray is return boolean value. Compare with false.

   var arr = [1,23,4,5];
    if(arr.isArray()===false){
     alert(' false ');
    }else{
      alert(' true ');
    }

OR simple

var arr = [1,23,4,5];
alert(arr.isArray());

edited May 15, 2014 at 3:43

answered May 15, 2014 at 3:43

Dinuka Thilanga

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Comments

malkam · Accepted Answer · 2014-05-15 03:44:40Z

0

$.isArray(arr) See below link

http://api.jquery.com/jquery.isarray/

answered May 15, 2014 at 3:44

malkam

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