$.isArray() some misunderstanding. jQuery

Question

I'm trying to check is p array or not. Am I trying to check true or where am i my making mistake. Actually now i'm learning jQuery.isArray. I think I make mistake in my code but i do not know where. Thank you

var p = ['foo',''];

if(!$(p).isArray()){
  alert('no');
}else{
  alert('yes');
}

FIDDLE

$.isArray is an utility function and not a dom element method and they should be used as @Rajaprabhu Aravindasamy demonstrated in his answer. The way you used is for dom elements method such as on, hide, remove, ... — php-dev
– php-dev, Commented May 17, 2014 at 10:24

Rajaprabhu Aravindasamy · Accepted Answer · 2014-05-17 10:09:34Z

4

You have to pass that array as a parameter in to the $.isArray() function.

Try,

if(!$.isArray(p)){
  alert('no');
}else{
  alert('yes');
}

DEMO

answered May 17, 2014 at 10:09

Rajaprabhu Aravindasamy

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