Check if a string variable is empty in batch script

Question

I am trying to write a batch script to get a string in a variable and check if it is empty, and if it is empty then it is directed to a loop. The below code represents the problem

:loop
set /p cide=
IF NOT "a%1"=="a" (set cide="%1")
IF [%1]==[] goto loop
ELSE
echo IDE entered
TIMEOUT 5 > NUL

The program starts to loop again even if i give a string.

I tried to put IF [%cide%]==[] goto loop or IF %cide%==[] goto loop it gave an error stating "ELSE" not recognized.

Any help is appreciated. Thanks

if not defined cide goto loop

aschipfl
– aschipfl

2016-09-24 21:05:04 +00:00
Commented Sep 24, 2016 at 21:05 — aschipfl
– aschipfl, Commented Sep 24, 2016 at 21:05

Hackoo · Accepted Answer · 2016-09-24 18:38:13Z

15

You can try something like that :

@echo off
:loop
cls & Color 0A
echo Type what you want !
set /p "cide="
IF "%cide%"=="" ( 
    Cls & Color 0C
    echo You must enter something
    Timeout /T 2 /NoBreak>nul
    goto loop
) ELSE (
    Goto Next
)

:Next
Cls
echo %cide% is entered
pause

answered Sep 24, 2016 at 18:38

Hackoo

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1 Comment

susil95 Over a year ago

Thanks @Hackoo, this worked. I tried the same but with different structure from what have you written, it gave either error or exits out. Very thanks man!!!

NIMISHAN · Accepted Answer · 2019-01-04 05:53:00Z

6

@echo off
:loop
cls & Color 0A
echo Type what you want !
set /p "cide="
IF [%cide%]==[] (
     Cls & Color 0C
     echo You must enter something
     choice /d y /t 2 > nul
     goto loop              
) ELSE (
     Goto Next
 )

:Next
Cls
echo %cide% is entered
pause

edited Jan 4, 2019 at 5:53

NIMISHAN

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answered Jan 4, 2019 at 3:29

user10865636

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1 Comment

stefanB Over a year ago

Any insight when using [] is better than quotes in the check ?

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